We are given that:
The element X has a dinegative ion with 10 electrons and 8 neutrons. The atomic number (Z) of element X is 10 (because the number of electrons in a neutral atom equals the atomic number).
The element Y has a dipositive ion with 12 protons. The number of neutrons in Y is 1.5 times the number of electrons in X. From the information, the number of protons in Y is 12.
Since the number of neutrons in Y is 1.5 times the number of electrons in X (which is 10), the number of neutrons in Y is: \[ \text{Neutrons in Y} = 1.5 \times 10 = 15 \] Now, to calculate the mass numbers: - The mass number of X is the sum of the protons and neutrons in the atom, which is: \[ \text{Mass number of X} = 10 \, (\text{protons}) + 8 \, (\text{neutrons}) = 18 \] - The mass number of Y is the sum of the protons and neutrons in the atom, which is: \[ \text{Mass number of Y} = 12 \, (\text{protons}) + 15 \, (\text{neutrons}) = 27 \] Therefore, the ratio of the mass numbers of X and Y is: \[ \text{Mass number ratio} = \frac{18}{27} = \frac{2}{3} \]
The correct option is (B) : \(2:3\)
For the reaction:
\[ 2A + B \rightarrow 2C + D \]
The following kinetic data were obtained for three different experiments performed at the same temperature:
\[ \begin{array}{|c|c|c|c|} \hline \text{Experiment} & [A]_0 \, (\text{M}) & [B]_0 \, (\text{M}) & \text{Initial rate} \, (\text{M/s}) \\ \hline I & 0.10 & 0.10 & 0.10 \\ II & 0.20 & 0.10 & 0.40 \\ III & 0.20 & 0.20 & 0.40 \\ \hline \end{array} \]
The total order and order in [B] for the reaction are respectively: