Question

A cycloalkene (X) is treated with Br\(_2\) and compound (Y) is formed with C : Br ratio 3 : 1. One mole of X required 1 mol of Br\(_2\). Find the composition of 'Br' in Y compound (percentage).

Hint:

To find the percentage composition of an element in a compound, divide the number of atoms of the element by the total atoms, then multiply by 100.

Answer 1

Correct Answer: 66

Step 1: Analyze the reaction.
The reaction involves the addition of Br\(_2\) to a cycloalkene. The C : Br ratio is 3 : 1, indicating that three carbon atoms are involved for every one bromine atom in the product. Step 2: Calculate the percentage of Br in the product.
For each mole of X, one mole of Br\(_2\) is consumed, and each molecule of the product contains 1 bromine atom for 3 carbon atoms. Therefore, the percentage of bromine in the product is: \[ \text{Percentage of Br} = \frac{1}{3 + 1} \times 100 = 66\%. \] Final Answer: \[ \boxed{66\%}. \]