Correct answer: 30 V
Explanation:
Using Ohm’s Law:
\[ V = IR \] where:
\( I = 1.5 \ \text{A} \) (current)
\( R = 20 \ \Omega \) (resistance)
Substituting the values:
\[ V = 1.5 \times 20 = 30 \ \text{V} \]
Hence, the potential difference across the conductor is: 30 V.
The current passing through the battery in the given circuit, is:
A constant voltage of 50 V is maintained between the points A and B of the circuit shown in the figure. The current through the branch CD of the circuit is :