Question:

A cup of tea cools from $80^{\circ} C$ to $60^{\circ} C$ in one minute. The ambient temperature is $30^{\circ} C$. In cooling from $60^{\circ} C$ to $50^{\circ} C$. It will take:

Updated On: Jun 7, 2022
  • 50 sec
  • 90 sec
  • 60 sec
  • 48 sec
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The Correct Option is D

Solution and Explanation

Rate of cooling $\alpha$ excess of temperature
$\frac{80^{\circ}-60^{\circ}}{60^{\circ}}=K\left(\frac{80^{\circ}+60^{\circ}}{2}-30^{\circ}\right) $
$\frac{1}{3}=K(4)\,\,\,\,...(1) $
$\frac{60^{\circ}-50^{\circ}}{t}= K \left(\frac{60^{\circ}+50^{\circ}}{2}-30^{\circ}\right)$
$\frac{10}{t}=K(25)\,\,\,\,...(2)$
Dividing equation (1) by (2), we get
$\frac{t}{30}=\frac{40}{25}$
or $t=\frac{40}{25} \times 30$
$=48\, \sec$
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Concepts Used:

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Anything that has mass or occupies space in the universe is commonly known as matter. There are five properties of matters namely chemical, mechanical, thermal, dimensional, and physical properties.

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Thermal Conductivity:

This property is interconnected to the conductivity of heat. The amount of heat regulated by the material is directly proportional to the conductivity of the material. Not all objects have the capacity to conduct heat throughout their bodies. Insulators are such objects which do not have the property to conduct heat throughout their body.

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