Question:

A cricket ball of mass 50 g and velocity 50 cm/s is stopped in 0.5 s. What is the force applied?

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Use \( F = \frac{mv}{t} \) when object is brought to rest; watch units carefully.
Updated On: May 19, 2025
  • 0.07 N
  • 0.05 N
  • 5 N
  • 7 N
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The Correct Option is B

Solution and Explanation

Convert to SI units: Mass = 0.05 kg, Velocity = 0.5 m/s, Time = 0.5 s Force \( F = \frac{mv}{t} = \frac{0.05 \times 0.5}{0.5} = 0.05\ \text{N} \)
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