• Let the object-screen distance $L = 1\ \text{m}$ and separation between lens positions $d = 0.2\ \text{m}$.
• For lens displacement method: $f = \dfrac{L^2 - d^2}{4L} = \dfrac{1^2 - 0.2^2}{4 \cdot 1} = \dfrac{1 - 0.04}{4} = 0.24\ \text{m} = 24\ \text{cm}$. Wait, the formula is correct: $f = \dfrac{L^2 - d^2}{4L} = 0.24\ \text{m}$, so correct answer is (2) 24 cm.
• Hence, focal length = 24 cm.