
(i) Let ABC be a conical tent.
Height (h) of conical tent = 10 m
Radius (r) of conical tent = 24 m
Let the slant height of the tent be l.
In \(∆\)ABO, AB2 = AO2 + BO2
l2 = h2 + r2
= (10 m)2 + (24 m)2
I= \(\sqrt{676}\)
= 26 m
Therefore, the slant height of the tent is 26 m.
(ii) curved surface area of the cone = \(\pi rl\)
= \(\frac{22}{7}\) × 24 m × 26 m
= \(\frac{13728}{7}\)m²
The cost of the canvas required to make the tent, at \(₹\) 70 per m² = 70 × Curved surface area of the cone
= \(\frac{13728}{7}\) × 70
= \(₹\)137280
Thus, slant height of the tent is 26 m and the cost of the canvas is ₹ 137280.
(i) The kind of person the doctor is (money, possessions)
(ii) The kind of person he wants to be (appearance, ambition)
ABCD is a quadrilateral in which AD = BC and ∠ DAB = ∠ CBA (see Fig. 7.17). Prove that
(i) ∆ ABD ≅ ∆ BAC
(ii) BD = AC
(iii) ∠ ABD = ∠ BAC.
