Question:

A compound is formed by cation C and anion A. The anions form hexagonal close packed (hep) lattice and the cations occupy 75% of octahedral voids. The formula of the compound is :

Updated On: Jul 13, 2024
  • $C_3A_4$
  • $C_4A_3$
  • $C_2A_3$
  • $C_3A_2$
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The Correct Option is A

Solution and Explanation

$ \bullet$ Anions(A) are in hcp, so number of anions (A) = 6
Cations(C) are in 75% O.V., so number of cations (C)
$ = 6 \times \frac{3}{4}$
$ = \frac{18}{4}$
$ = \frac{9}{2}$
$\bullet$ So formula of compound will be
$C_{\frac{9}{2} } A_6 \Rightarrow \; C_9A_{12}$
$C_9 A_{12} \Rightarrow C_3A_4$
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Concepts Used:

Solid State

Solids are substances that are featured by a definite shape, volume, and high density. In the solid-state, the composed particles are arranged in several manners. Solid-state, in simple terms, means "no moving parts." Thus solid-state electronic devices are the ones inclusive of solid components that don’t change their position. Solid is a state of matter where the composed particles are arranged close to each other. The composed particles can be either atoms, molecules, or ions. 

Solid State

Types of Solids:

Based on the nature of the order that is present in the arrangement of their constituent particles solids can be divided into two types;

  • Amorphous solids behave the same as super cool liquids due to the arrangement of constituent particles in short-range order. They are isotropic and have a broad melting point (range is about greater than 5°C).
  • Crystalline solids have a fixed shape and the constituent particles are arranged in a long-range order.