For a closed organ pipe}, the frequency of the seventh overtone is:
\[f_c = (2n + 1) \frac{v}{4\ell}, \quad n = 7.\]
\[f_c = 15 \frac{v}{4\ell}.\]
For an open organ pipe, the frequency of the seventh overtone is:
\[f_o = (n + 1) \frac{v}{2\ell}, \quad n = 7.\]
\[f_o = 8 \frac{v}{2\ell}.\]
The ratio is:
\[\frac{f_c}{f_o} = \frac{15}{16} = \frac{a - 1}{a}.\]
Solving:
\[a = 16.\]
Final Answer: $16$.
20 mL of sodium iodide solution gave 4.74 g silver iodide when treated with excess of silver nitrate solution. The molarity of the sodium iodide solution is _____ M. (Nearest Integer value) (Given : Na = 23, I = 127, Ag = 108, N = 14, O = 16 g mol$^{-1}$)