To solve the problem, we need to find the true time when the clock shows 10 p.m., given that the clock gains 2 minutes every hour starting from 6 a.m.
- Clock set time: 6 a.m.
- Clock gain: 2 minutes every hour
- Clock shows: 10 p.m.
- True time: Actual time elapsed when the faulty clock shows 10 p.m.
- The clock gains 2 minutes per hour.
- The clock runs from 6 a.m. to 10 p.m., which is 16 hours according to the faulty clock.
The clock gains 2 minutes every hour, so in 1 hour of true time, the clock shows \( 60 + 2 = 62 \) minutes.
Let the actual time elapsed be \( t \) hours.
The time shown by the clock after \( t \) hours is:
\( \text{Clock time} = \frac{62}{60} \times t = \frac{31}{30} t \)
We know the clock shows 16 hours (from 6 a.m. to 10 p.m.):
\[ \frac{31}{30} t = 16 \]
\[ t = \frac{16 \times 30}{31} = \frac{480}{31} \approx 15.48 \text{ hours} \]
0.48 hours =\( 0.48 \times 60 = 28.8 \text{ minutes} \approx 29 \text{ minutes}\)
More precisely, \( \frac{480}{31} \) hours equals:
Hours = 15 hours
Minutes = \( \frac{480}{31} - 15 = \frac{480 - 465}{31} = \frac{15}{31} \) hours
\( \frac{15}{31} \times 60 \approx 29.03 \) minutes, which rounds closer to 29 minutes, but if we consider exact time:
Minutes = 28.8 minutes, closer to 28 minutes and 48 seconds.
Starting from 6 a.m., after approximately 15 hours 28 minutes, the true time is:
6:00 a.m. + 15 hours 28 minutes = 9:28 a.m. + 12 hours = 9:28 p.m.
The true time when the clock shows 10 p.m. is approximately 9:28 p.m.
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