Question:

A clock gains 2 minutes every hour. Then the angle traversed by the second hand in one minute is:

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“Gains $g$ minutes per hour” $\Rightarrow$ speed factor $=\dfrac{60+g}{60}$. Multiply the usual angular sweep by this factor.
Updated On: Aug 13, 2025
  • $360^\circ$
  • $370^\circ$
  • $390^\circ$
  • $372^\circ$
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The Correct Option is D

Solution and Explanation

A gain of $2$ minutes per \emph{real} hour means the clock advances $62$ “clock minutes” in $60$ real minutes. So its rate factor is \[ \text{rate}=\frac{62}{60}=\frac{31}{30}. \] Normally, the second hand sweeps $360^\circ$ in one minute. With the faster rate, in one real minute it sweeps \[ 360^\circ\times\frac{31}{30}=372^\circ. \] Hence, $372^\circ$.
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