Given that \( L = 5 \, m \), \( T = 100 \, kN.m \), and \( \frac{GJ}{L} = 50,000 \, kN.m^2/rad \), we can proceed with the calculations.
1. Rotation at the free end:
The rotation \( \theta \) at the free end of a shaft due to an applied torque is given by the formula:
\[
\theta = \frac{T \cdot L}{GJ}
\]
Where:
\[
T = 100 \, kN.m = 100 \times 10^3 \, N.m, L = 5 \, m, GJ = 50,000 \, kN.m^2/rad = 50,000 \times 10^3 \, N.m^2/rad
\]
Substituting the values:
\[
\theta = \frac{100 \times 10^3 \times 5}{50,000 \times 10^3} = 0.01 \, rad
\]
Thus, Statement i) is correct.
2. Torsional Strain Energy:
The torsional strain energy \( U \) stored in a shaft due to torque is given by the formula:
\[
U = \frac{T^2 L}{2 GJ}
\]
Substituting the given values:
\[
U = \frac{(100 \times 10^3)^2 \times 5}{2 \times 50,000 \times 10^3}
\]
\[
U = \frac{(10^7) \times 5}{10^6} = 5 \, kN.m
\]
Thus, Statement ii) is incorrect because the torsional strain energy is \( 5 \, kN.m \), not \( 1.0 \, kN.m \).
Conclusion:
The correct option is (B) – Statement i) is correct, but Statement ii) is wrong.