To analyze the given problem, we use Faraday's Law of Induction and Lenz's Law. The setup involves a circular coil placed near a current-carrying conductor, both lying on the plane of the paper. The induced current in the loop is clockwise.
The current in the wire is time-dependent and downward.
Final Answer: (A): time-dependent and downward
In this scenario, the loop is positioned to the right of the current-carrying wire, even though it might seem as if it's on the left side. This is because, when you move in the direction of the current, the loop is situated to the right.
Now, as the current diminishes, the induced current within the loop is in a clockwise direction (S), as illustrated in the diagram.
Correct Option: (A): time-dependent and downward
Show that the energy required to build up the current \( I \) in a coil of inductance \( L \) is \( \frac{1}{2} L I^2 \).
A circular coil of diameter 15 mm having 300 turns is placed in a magnetic field of 30 mT such that the plane of the coil is perpendicular to the direction of the magnetic field. The magnetic field is reduced uniformly to zero in 20 ms and again increased uniformly to 30 mT in 40 ms. If the EMFs induced in the two time intervals are \( e_1 \) and \( e_2 \) respectively, then the value of \( e_1 / e_2 \) is:
A quantity \( X \) is given by: \[ X = \frac{\epsilon_0 L \Delta V}{\Delta t} \] where:
- \( \epsilon_0 \) is the permittivity of free space,
- \( L \) is the length,
- \( \Delta V \) is the potential difference,
- \( \Delta t \) is the time interval.
The dimension of \( X \) is the same as that of:
Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-
The electromagnetic induction is mathematically represented as:-
e=N × d∅.dt
Where