Question:
A circle S touches the Y-axis at \( (0, 3) \) and makes an intercept of length 8 units on the X-axis. If the center C of the circle S lies in the second quadrant, then the distance of C from the point \( (-2, -1) \) is:
A circle S touches the Y-axis at \( (0, 3) \) and makes an intercept of length 8 units on the X-axis. If the center C of the circle S lies in the second quadrant, then the distance of C from the point \( (-2, -1) \) is:
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For problems involving circles, use the geometry of tangents and the distance formula to calculate distances from the center.
Updated On: May 15, 2025
- \( \sqrt{13} \)
- \( 10 \)
- \( 5 \)
- \( \sqrt{2} \)
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The Correct Option is C
Solution and Explanation
The center of the circle lies in the second quadrant, and the distance from the center to the point \( (-2, -1) \) is calculated by using the distance formula. The correct answer is \( 5 \).
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