Weight of liquid 1 per liter is 1000 gm, and for liquid 2, it is 800 gm.
The weight of the mixture per liter, obtained by mixing the two liquids = 2×480 gm = 960 gm.
Using the allegation rule,
The ratio of the
Quantity of liquid 1 to liquid 2 is calculated as:
= \(\frac{960 - 800}{1000 - 960} = \frac{4}{1}\).
This implies that the liquids are mixed in a ratio of 4:1.
Consequently, the percentage of liquid 1 in the mixture is determined as = \(\frac{4}{(4 + 1)} \times 100\), resulting in 80%.