Weight per liter of liquid 1 = 1000 gm
Weight per liter of liquid 2 = 800 gm
Weight per liter of the mixture = \( \frac{2 \times 480}{1+1} = 960 \) gm
We find the ratio of quantities of liquid 1 and liquid 2 as: \[ \frac{960 - 800}{1000 - 960} = \frac{160}{40} = \frac{4}{1} \]
So, the liquids are mixed in the ratio 4:1.
\[ \frac{4}{4+1} \times 100 = \frac{4}{5} \times 100 = 80\% \]