Question:
A charged particle is suspended in equilibrium in a uniform vertical electric field of intensity $20000\, V / m$. If mass of the particle is $9.6 \times 10^{-16} kg$, the charge on it and excess number of electrons on the-particle respectively are $\left( g =10\, m / s ^{2}\right)$
A charged particle is suspended in equilibrium in a uniform vertical electric field of intensity $20000\, V / m$. If mass of the particle is $9.6 \times 10^{-16} kg$, the charge on it and excess number of electrons on the-particle respectively are $\left( g =10\, m / s ^{2}\right)$
Updated On: May 12, 2022
- $4.8 \times 10^{-19} C,\, 3$
- $5.8 \times 10^{-19} C,\, 4$
- $3.8 \times 10^{-19} C,\, 2$
- $2.8 \times 10^{-19} C,\, 1$
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The Correct Option is A
Solution and Explanation
Charge on the particle is given by
$q E =m g$ or $q=\frac{m g}{E}$
$=\frac{9.6 \times 10^{-16} \times 10}{20000}=4.8 \times 10^{-19}$
When there is an excess of $n$ electrons on the particle, then
$q=n e$
So, $n=\frac{q}{e}=\frac{4.8 \times 10^{-19}}{1.6 \times 10^{-19}}=3$
$q E =m g$ or $q=\frac{m g}{E}$
$=\frac{9.6 \times 10^{-16} \times 10}{20000}=4.8 \times 10^{-19}$
When there is an excess of $n$ electrons on the particle, then
$q=n e$
So, $n=\frac{q}{e}=\frac{4.8 \times 10^{-19}}{1.6 \times 10^{-19}}=3$
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Concepts Used:
Electrostatic Potential
The electrostatic potential is also known as the electric field potential, electric potential, or potential drop is defined as “The amount of work that is done in order to move a unit charge from a reference point to a specific point inside the field without producing an acceleration.”
SI Unit of Electrostatic Potential:
SI unit of electrostatic potential - volt
Other units - statvolt
Symbol of electrostatic potential - V or φ
Dimensional formula - ML2T3I-1
Electric Potential Formula:
The electric potential energy of the system is given by the following formula:
U = 1/(4πεº) × [q1q2/d]
Where q1 and q2 are the two charges that are separated by the distance d.