We are given a charge \( q = 2 \, \mu\text{C} = 2 \times 10^{-6} \, \text{C} \) placed in an electric field of intensity \( E = 4 \times 10^3 \, \text{N/C} \), and we need to find the force experienced by the charge.
Step 1: Use the formula for the force in an electric field
The force experienced by a charge in an electric field is given by the formula:
\[
F = E \times q
\]
Where:
- \( F \) is the force,
- \( E \) is the electric field intensity,
- \( q \) is the charge.
Step 2: Substitute the known values
Substitute \( E = 4 \times 10^3 \, \text{N/C} \) and \( q = 2 \times 10^{-6} \, \text{C} \) into the formula:
\[
F = (4 \times 10^3) \times (2 \times 10^{-6})
\]
\[
F = 8 \times 10^{-3} \, \text{N}
\]
Step 3: Conclusion
The force experienced by the charge is \( 8 \times 10^{-3} \, \text{N} \).
Answer: The force experienced by the charge is \( 8 \times 10^{-3} \, \text{N} \), so the correct answer is option (1).