A carnot engine has an efficiency of 50% when its source is at a temperature 327°C. The temperature of the sink is:
- 200°C
- 27°C
- 15°C
- 100°C
The Correct Option is B
Solution and Explanation
The correct option is (B): 27°C
The efficiency of Carnot engine,
%\(\eta\)=(1-\( \frac{T_{sink}}{T_{source}}\times100\))
\(T_{source}=327^{\circ}C=600K\)
\(50=(1- \frac{T_{sink}}{600})\times100\)
\( \frac{1}{2}=1- \frac{T_{sink}}{600}\)
\(T_{sink}=300K\)
So the temperature of the sink is= 327-300=27\(^{\circ}\)C
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