Question

A capacitor of 100 \(\mu F\) is charged to 100 volt. The energy stored in it will be

• A. 0.5 joule
• B. 5 joule
• C. 50 joule
• D. 100 joule

Hint:

The energy stored in a capacitor is proportional to the square of the voltage and the capacitance.

Answer 1

The Correct Option is A

Step 1: Formula for energy stored in a capacitor.
The energy (\( E \)) stored in a capacitor is given by the formula: \[ E = \frac{1}{2} C V^2 \] where: - \( C \) is the capacitance in farads (F), - \( V \) is the voltage in volts (V). Step 2: Given values.
- \( C = 100 \, \mu F = 100 \times 10^{-6} \, F \), - \( V = 100 \, V \). Substituting these values into the formula: \[ E = \frac{1}{2} \times (100 \times 10^{-6}) \times (100)^2 = 0.5 \, \text{joules} \] Step 3: Conclusion.
Thus, the energy stored in the capacitor is 0.5 joules.
\[ \boxed{0.5 \, \text{joules}} \]