Question:

A bus is moving on a straight road towards north with a uniform speed of 50 km/hour then it turns left through 90^{\circ}. If the speed remains unchanged after turning, the increase in the velocity of bus in the turning process is

Updated On: May 4, 2024
  • 70.7 km/hr along south-west direction
  • zero
  • 50 km/hr along west
  • 70.7 km/hr along north-west direction
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The Correct Option is A

Solution and Explanation

v1 v_1 50 km/hr due north
v2 v_2 50 km/hr due west
- v1 v_1 50 km/hr due south
Magnitude of change in velocity
= v2v1=v2+(v1) | \overrightarrow{v_2} - \overrightarrow{v_1} | = | \overrightarrow{v_2} + ( - \overrightarrow{v_1}) |
= v22+(v1)2 \sqrt{ v_2^2 + ( - v_1)^2 }
= (50)2+(50)2 \sqrt{ ( 50)^2 + (50)^2 }
= 70.7 km/hr along south-west direction
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Concepts Used:

Motion in a Plane

It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions. 

Equations of Plane Motion

The equations of motion in a straight line are:

v=u+at

s=ut+½ at2

v2-u2=2as

Where,

  • v = final velocity of the particle
  • u = initial velocity of the particle
  • s = displacement of the particle
  • a = acceleration of the particle
  • t = the time interval in which the particle is in consideration