Momentum of rifle = Momentum of bullet
$m_{1} v_{1}=m_{2} v_{2}$, Also $m_{1} >m_{2}$
$\frac{\text { K.E. of rifte }}{\text { K.E. of bullet }}=\frac{\frac{1}{2} m_{1} v_{1}^{2}}{\frac{1}{2} m_{2} v_{2}^{2}}$
$=\frac{m_{1}^{2} v_{1}^{2}}{m_{1}} \frac{m_{2}}{m_{2}^{2} v_{2}^{2}}=\frac{m_{2}}{m_{1}}$
K.E. of rifle is less than $K . E$. of bullet.