Question:

A brown ring appears in the test for

Updated On: Aug 15, 2022
  • nitrate
  • nitrite
  • bromide
  • iron
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The Correct Option is A

Solution and Explanation

At the junction of salt formation and $FeSO _{4}$ solution with conc. $H _{2} SO _{4}$ a brown ring is obtained $\left( FeSO _{4} \cdot NO \right) .$ $\underset{\text{nitrate salt soluble in water}}{NO _{3}^{-}}+6 FeSO _{4}+3 H _{2} SO _{4} \rightarrow 3 Fe _{2}\left( SO _{4}\right)_{3}$ $ FeSO _{4}+ NO \rightarrow \underset{\text{brown ring}}FeSO _{4} \cdot NO$
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Concepts Used:

P-Block Elements

  • P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
  • P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.

P block elements consist of: