Question:
A brown ring appears in the test for
A brown ring appears in the test for
Updated On: Aug 15, 2022
- nitrate
- nitrite
- bromide
- iron
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The Correct Option is A
Solution and Explanation
At the junction of salt formation and $FeSO _{4}$
solution with conc. $H _{2} SO _{4}$ a brown ring is
obtained $\left( FeSO _{4} \cdot NO \right) .$
$\underset{\text{nitrate salt soluble in water}}{NO _{3}^{-}}+6 FeSO _{4}+3 H _{2} SO _{4} \rightarrow 3 Fe _{2}\left( SO _{4}\right)_{3}$
$ FeSO _{4}+ NO \rightarrow \underset{\text{brown ring}}FeSO _{4} \cdot NO$
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Concepts Used:
P-Block Elements
- P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
- P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.
P block elements consist of:
- Group 13 Elements: Boron family
- Group 14 Elements: Carbon family
- Group 15 Elements: Nitrogen family
- Group 16 Elements: Oxygen family
- Group 17 Elements: Fluorine family
- Group 18 Elements: Neon family