Question:

A box contains 7 red marbles and 9 green marbles. If a marble is drawn at random from the box, then the probability of not getting a red marble is

Updated On: Apr 17, 2025
  • \(\frac{7}{16}\)
  • \(\frac{5}{16}\)
  • \(\frac{3}{16}\)
  • \(\frac{9}{16}\)
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The Correct Option is D

Solution and Explanation

To solve the problem, we need to find the probability of not getting a red marble when a marble is drawn at random from a box containing 7 red marbles and 9 green marbles.

1. Total Number of Marbles:
The total number of marbles = 7 (red) + 9 (green) = 16 marbles

2. Favourable Outcomes:
The favourable outcome for the event "not getting a red marble" is drawing a green marble.
Number of green marbles = 9

3. Probability Formula:

Probability = \( \frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}} \)

So, Probability = \( \frac{9}{16} \)

Final Answer:
The probability of not getting a red marble is \( \frac{9}{16} \)

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