Question:

A body starts from rest and accelerates uniformly at 2 m/s\(^2\). What is the distance covered in 5 seconds?

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Use equations of motion to calculate distance under uniform acceleration.
Updated On: May 20, 2025
  • 20 m
  • 25 m
  • 50 m
  • 100 m
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The Correct Option is C

Solution and Explanation


- Given: initial velocity \(u = 0\) (starts from rest), acceleration \(a = 2\, \text{m/s}^2\), time \(t = 5\, \text{s}\)
- Use the equation of motion for distance covered under uniform acceleration: \[ s = ut + \frac{1}{2} a t^2 \] - Substitute values: \[ s = 0 \times 5 + \frac{1}{2} \times 2 \times (5)^2 = 1 \times 25 = 25\, \text{m} \] - But since answer 25 m is option (B), let's double-check: Yes, \(s = \frac{1}{2} \times 2 \times 25 = 25\) m. So correct answer is (B) 25 m. % Final answer Answer: \(\boxed{\text{B}}\)
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