Question:

A body of mass $m$ rises to a height $h=\frac{R}{5}$ from the earth's surface where $R$ is earth's radius. If $g$ is acceleration due to gravity at the earth's surface, the increase in potential energy will be

Updated On: Jul 2, 2022
  • $mgh$
  • $ \frac{4}{5}mgh$
  • $ \frac{5}{6}mgh$
  • $ \frac{6}{7} mgh$
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

Increase in gravitational potential energy $=\left[-\frac{G M m}{h+ R}\right]-\left[-\frac{G M m}{R}\right]$ $=\left[-\frac{G M m}{R+\frac{R}{5}}\right]-\left[-\frac{G M m}{R}\right]$ $\left[\because h=\frac{R}{5}\right] $ $=\frac{G M m}{R}-\frac{G M m \times 5}{6 R}$ $=\frac{G M m}{R}\left[1-\frac{5}{6}\right]=\frac{G M m}{R} \times \frac{1}{6}$ $=\frac{m g R^{2}}{6 R}=\frac{1}{6} m g R=\frac{5}{6} m g h$ $[\because R=5 h]$
Was this answer helpful?
0
0

Questions Asked in AIIMS exam

View More Questions

Concepts Used:

Gravitational Potential Energy

The work which a body needs to do, against the force of gravity, in order to bring that body into a particular space is called Gravitational potential energy. The stored is the result of the gravitational attraction of the Earth for the object. The GPE of the massive ball of a demolition machine depends on two variables - the mass of the ball and the height to which it is raised. There is a direct relation between GPE and the mass of an object. More massive objects have greater GPE. Also, there is a direct relation between GPE and the height of an object. The higher that an object is elevated, the greater the GPE. The relationship is expressed in the following manner:

PEgrav = mass x g x height

PEgrav = m x g x h

Where,

m is the mass of the object,

h is the height of the object

g is the gravitational field strength (9.8 N/kg on Earth) - sometimes referred to as the acceleration of gravity.