Question

A body of mass \(M\) moving with velocity \(V\) explodes into two equal parts. If one part comes to rest and the other part moves with velocity \(V_0\), what would be the value of \(V_0\)?

• A. \(V\)
• B. \( \dfrac{V}{\sqrt{2}} \)
• C. \(2V\)
• D. \(4V\)

Hint:

In explosion problems, total momentum remains conserved even though kinetic energy changes.

Answer 1

The Correct Option is C

Step 1: Apply conservation of momentum.
Initial momentum of the body is \[ MV \]

Step 2: Write momentum after explosion.
Mass of each part after explosion is \( \frac{M}{2} \). One part comes to rest, and the other moves with velocity \(V_0\).
\[ MV = \frac{M}{2} \cdot V_0 \]

Step 3: Solve for \(V_0\).
\[ V_0 = 2V \]