Question:
A body of mass 6 kg is moved with uniform speed on a rough horizontal surface through a distance of 200 cm. If the coefficient of kinetic friction between the surface and the body is 0.1, then the work done against friction is (Acceleration due to gravity \(g = 10\, m/s^2\)):
A body of mass 6 kg is moved with uniform speed on a rough horizontal surface through a distance of 200 cm. If the coefficient of kinetic friction between the surface and the body is 0.1, then the work done against friction is (Acceleration due to gravity \(g = 10\, m/s^2\)):
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Work done against friction = friction force \(\times\) displacement.
Updated On: Jun 2, 2025
- 12 J
- 24 J
- 36 J
- 48 J
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The Correct Option is A
Solution and Explanation
Friction force:
\[
f = \mu mg = 0.1 \times 6 \times 10 = 6\, N
\]
Distance moved:
\[
d = 200\, cm = 2\, m
\]
Work done against friction:
\[
W = f \times d = 6 \times 2 = 12\, J
\]
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