Question:

A body moving along a circular path of radius RR with velocity vv, has centripetal acceleration a. If its velocity is made equal to 2v2v, then its centripetal acceleration is

Updated On: Jun 3, 2024
  • 4a 4\,a
  • 2a 2\,a
  • a4 \frac{a}{4}
  • a2 \frac{a}{2}
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The Correct Option is A

Solution and Explanation

The centripetal acceleration a=v2Ra=\frac{v^{2}}{R}
or av2a \propto v^{2}
or a1a2=v12v22\frac{a_{1}}{a_{2}}=\frac{v_{1}^{2}}{v_{2}^{2}}
=aa2=v2(2v)2=14=\frac{a}{a_{2}}=\frac{v^{2}}{(2 v)^{2}}=\frac{1}{4}
or a2=4aa_{2}=4\, a
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Concepts Used:

Motion in a Plane

It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions. 

Equations of Plane Motion

The equations of motion in a straight line are:

v=u+at

s=ut+½ at2

v2-u2=2as

Where,

  • v = final velocity of the particle
  • u = initial velocity of the particle
  • s = displacement of the particle
  • a = acceleration of the particle
  • t = the time interval in which the particle is in consideration