Question:

A body is thrown with a velocity of \( 9.8 \) m/s making an angle of \( 30^\circ \) with the horizontal. It will hit the ground after a time:

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The total time of flight for projectile motion is: \[ T = \frac{2 u \sin \theta}{g} \] This formula is useful for determining how long a projectile remains in the air.
Updated On: Mar 24, 2025
  • \( 3.0 \) s
  • \( 2.0 \) s
  • \( 1.5 \) s
  • \( 1.0 \) s
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The Correct Option is D

Solution and Explanation

Step 1: {Use the time of flight formula}
Time of flight for a projectile is given by: \[ T = \frac{2 u \sin \theta}{g} \] Step 2: {Substituting values}
\[ T = \frac{2 \times 9.8 \times \sin 30^\circ}{9.8} \] Step 3: {Solve for \( T \)}
\[ T = \frac{2 \times 9.8 \times \frac{1}{2}}{9.8} \] \[ T = 1 { sec} \] Thus, the correct answer is (D) 1.0 s.
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