A body is thrown with a velocity of \( 9.8 \) m/s making an angle of \( 30^\circ \) with the horizontal. It will hit the ground after a time:
Show Hint
The total time of flight for projectile motion is:
\[
T = \frac{2 u \sin \theta}{g}
\]
This formula is useful for determining how long a projectile remains in the air.
Step 1: {Use the time of flight formula}
Time of flight for a projectile is given by:
\[
T = \frac{2 u \sin \theta}{g}
\]
Step 2: {Substituting values}
\[
T = \frac{2 \times 9.8 \times \sin 30^\circ}{9.8}
\]
Step 3: {Solve for \( T \)}
\[
T = \frac{2 \times 9.8 \times \frac{1}{2}}{9.8}
\]
\[
T = 1 { sec}
\]
Thus, the correct answer is (D) 1.0 s.