Question:

A body is moving in a circular path with acceleration $a$. If its velocity gets doubled, find the ratio of acceleration after and before the change :

Updated On: Jul 27, 2022
  • 1:04
  • $ \frac{1}{4}:1 $
  • 2:01
  • 4:01
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The Correct Option is D

Solution and Explanation

In a circular motion $a =\frac{v^{2}}{r} $ $\therefore \frac{a_{2}}{a_{1}} =\left(\frac{v_{2}}{v_{1}}\right)^{2} $ $=\left(\frac{2 v_{1}}{v_{1}}\right)^{2}=4$
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Concepts Used:

Motion in a Plane

It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions. 

Equations of Plane Motion

The equations of motion in a straight line are:

v=u+at

s=ut+½ at2

v2-u2=2as

Where,

  • v = final velocity of the particle
  • u = initial velocity of the particle
  • s = displacement of the particle
  • a = acceleration of the particle
  • t = the time interval in which the particle is in consideration