The correct option is(A): 150 J.
\(\overrightarrow{F}=(-2\widehat{i}+15\widehat{j}+6\widehat{k})\)N and distance (d) = 10\(\widehat{j}\, m\).
Work done
W=\(\overrightarrow{F}\cdot \overrightarrow{d}= (-2\widehat{i}+15\widehat{j}+6\widehat{k})\cdot (10\widehat{j})=150 N-m =150\, J\).
The current passing through the battery in the given circuit, is:
A bob of heavy mass \(m\) is suspended by a light string of length \(l\). The bob is given a horizontal velocity \(v_0\) as shown in figure. If the string gets slack at some point P making an angle \( \theta \) from the horizontal, the ratio of the speed \(v\) of the bob at point P to its initial speed \(v_0\) is :
A full wave rectifier circuit with diodes (\(D_1\)) and (\(D_2\)) is shown in the figure. If input supply voltage \(V_{in} = 220 \sin(100 \pi t)\) volt, then at \(t = 15\) msec: