Question:

A body, constrained to move in y-direction, is subjected to a force given by $\overrightarrow{F} = (-2\widehat{i}+15\widehat{j}+6\widehat{k})$N The work done by this force in moving the body through a distance of 10$\widehat{j}$ m along y-axis, is

Updated On: May 5, 2024
  • 150 J
  • 20 J
  • 190 J
  • 160 J
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The Correct Option is A

Solution and Explanation

The correct option is(A): 150 J.

\(\overrightarrow{F}=(-2\widehat{i}+15\widehat{j}+6\widehat{k})\)N and distance (d) = 10\(\widehat{j}\, m\)
Work done 
W=\(\overrightarrow{F}\cdot \overrightarrow{d}= (-2\widehat{i}+15\widehat{j}+6\widehat{k})\cdot (10\widehat{j})=150 N-m =150\, J\).

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