Question:

A boat which has a speed of $5\, km/h$ in still water crosses a river of width $1\, km$ along the shortest possible path in $15\, min$. The velocity of the river water in $km/h$ is

Updated On: Jul 5, 2022
  • 1
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  • $\sqrt {41}$
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The Correct Option is B

Solution and Explanation

Shortest possible path comes when absolute velocity of boatman comes perpendicular to river current as shown in figure. $ \hspace20mm t = \frac{\omega}{v_b}=\frac{\omega}{\sqrt{v^2_{br}-v^2_r}}$ $\therefore \hspace15mm = \frac{1}{4}=\frac{1}{\sqrt{25-v^2_r}}$ Solving this equation, we get $v_r=3\, km/h$ $\therefore$ Correct answer is (b).
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Concepts Used:

Motion in a Plane

It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions. 

Equations of Plane Motion

The equations of motion in a straight line are:

v=u+at

s=ut+½ at2

v2-u2=2as

Where,

  • v = final velocity of the particle
  • u = initial velocity of the particle
  • s = displacement of the particle
  • a = acceleration of the particle
  • t = the time interval in which the particle is in consideration