Assume,
Length of the boat \((L)\) = 6 meters
Breadth of the boat \((B)\) = 4 meters
Depth of sinking \((h)\) = 0.2 cm = 0.002 meters (converted into meter)
volume of water displaced \((V)\) = \(V = L \times B \times h\)
\(V\) = 6 × 4 × 0.002
\(V\) = 0.048 m3
mass of person \((p)\)
The density of water = \(1000 \frac{kg}{m^3}\)
\(m = p \times V\)
\(m\) = 1000 × 0.048
\(m\) = 48 kg
The correct option is (D):48 Kg