Question:

A block of mass $M$ is attached to the lower end of a vertical spring. The spring is hung from a ceiling and has force constant value $k$. The mass is released from rest with the spring initially unstretched. The maximum extension produced in the length of the spring will be

Updated On: Aug 24, 2023
  • 2Mg/k
  • 4Mg/k
  • Mg/2k
  • Mg/k
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The Correct Option is A

Solution and Explanation

Loss in grav. $PE =$ gain in spring $PE$
At maximum elongation
$Mgx =\frac{1}{2} kx ^{2}$
$x =\frac{2 Mg }{ k }$
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