Question:
A bird flies at an angle of $ 60^{\circ} $ to the horizontal. Its horizontal component of velocity is $ 10\, m\, s ^{-1} $ . Find the vertical component of velocity in $ m s ^{-1} $ .
A bird flies at an angle of $ 60^{\circ} $ to the horizontal. Its horizontal component of velocity is $ 10\, m\, s ^{-1} $ . Find the vertical component of velocity in $ m s ^{-1} $ .
Updated On: Jun 14, 2022
- $ 10 \sqrt 3 $
- $ \frac{10}{\sqrt{3}} $
- $ 5 $
- $ 26 $
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The Correct Option is A
Solution and Explanation
$\theta=60^{\circ}, u_{x}=10\,m\,s^{-1}, u_{y}=?$
As tan $\theta=\frac{u_{y}}{u_{x}} $
$\therefore u_{y}=u_{x} tan \,\theta=10\times\sqrt{3}$
$=10\sqrt{3}\,m\,s^{-1}$
As tan $\theta=\frac{u_{y}}{u_{x}} $
$\therefore u_{y}=u_{x} tan \,\theta=10\times\sqrt{3}$
$=10\sqrt{3}\,m\,s^{-1}$
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Concepts Used:
Motion in a Plane
It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions.
Equations of Plane Motion
The equations of motion in a straight line are:
v=u+at
s=ut+½ at2
v2-u2=2as
Where,
- v = final velocity of the particle
- u = initial velocity of the particle
- s = displacement of the particle
- a = acceleration of the particle
- t = the time interval in which the particle is in consideration