After the first polarizer: \(I_1 = \frac{I_0}{2}\)
After the second polarizer: \(I_2 = I_1 \cos^2 60^\circ = \frac{I_0}{2} \times \frac{1}{4} = \frac{I_0}{8}\)
After the third polarizer: \(I_3 = I_2 \cos^2 45^\circ = \frac{I_0}{8} \times \frac{1}{2} = \frac{I_0}{16}\)
Calculate the angle of minimum deviation of an equilateral prism. The refractive index of the prism is \(\sqrt{3}\). Calculate the angle of incidence for this case of minimum deviation also.
A bob of heavy mass \(m\) is suspended by a light string of length \(l\). The bob is given a horizontal velocity \(v_0\) as shown in figure. If the string gets slack at some point P making an angle \( \theta \) from the horizontal, the ratio of the speed \(v\) of the bob at point P to its initial speed \(v_0\) is :