Question:
A bar magnet of magnetic moment M = 0.5A m2 is under the influence of a magnetic field 8 T. Find the work done (J) to move the magnet from stable to unstable equilibrium position.
A bar magnet of magnetic moment M = 0.5A m2 is under the influence of a magnetic field 8 T. Find the work done (J) to move the magnet from stable to unstable equilibrium position.
Updated On: Apr 5, 2024
Hide Solution
Verified By Collegedunia
Correct Answer: 8
Solution and Explanation
The correct answer is 8J.
Was this answer helpful?
0
0
Top Questions on Magnetic Force
- A proton enters a uniform magnetic field $\vec{B} = 0.5 \hat{k} \ \text{T}$ with velocity $\vec{v} = 10^6 \hat{i} \ \text{m/s}$. The magnitude of the magnetic force on the proton is:
- BITSAT - 2025
- Physics
- Magnetic Force
- A square loop MNPK of side \( l \) carrying a current \( I_2 \) is kept close to a long straight wire in the same plane and the wire carries a steady current \( I_1 \) as shown in the figure. Obtain the magnitude of magnetic force exerted by the wire on the loop.
- CBSE CLASS XII - 2025
- Physics
- Magnetic Force
- A particle with charge \( q \) moving with velocity \( \vec{v} = v_0 \hat{i} \) enters a region with magnetic field \( \vec{B} = B_1 \hat{j} + B_2 \hat{k} \). The magnitude of force experienced by the particle is:
- CBSE CLASS XII - 2025
- Physics
- Magnetic Force
- A straight conductor is carrying a current of 2 A in the \( +x \) direction along it. A uniform magnetic field \( \vec{B} = (0.6 \hat{j} + 0.8 \hat{k}) \) T is switched on in the region. The force acting on 10 cm length of the conductor is:
- CBSE CLASS XII - 2025
- Physics
- Magnetic Force
- The force on a current-carrying conductor placed in a magnetic field becomes zero, when it is:
- TS POLYCET - 2025
- Physics
- Magnetic Force
View More Questions
Questions Asked in JEE Main exam
- Total number of non-bonded electrons present in \( \text{NO}_2 \); ion based on Lewis theory is:
- JEE Main - 2025
- Chemical bonding and molecular structure
Match List - I with List - II.
- JEE Main - 2025
- Thermodynamics
- The variance of the numbers 8, 21, 34, 47, \dots, 320, is:
- JEE Main - 2025
- Arithmetic Progression and Variance
- The value of \( (\sin 70^\circ)(\cot 10^\circ \cot 70^\circ - 1) \) is:
- JEE Main - 2025
- Trigonometric Identities
- Let A and B be the two points of intersection of the line \( y + 5 = 0 \) and the mirror image of the parabola \( y^2 = 4x \) with respect to the line \( x + y + 4 = 0 \). If \( d \) denotes the distance between A and B, and \( a \) denotes the area of \( \Delta SAB \), where \( S \) is the focus of the parabola \( y^2 = 4x \), then the value of \( (a + d) \) is:
- JEE Main - 2025
- Angle between a Line and a Plane
View More Questions