Question:

A ball of mass 50 g moving with a velocity of 10 ms$^{-1}$ is hit by a bat and the ball retraces back with a velocity of 20 ms$^{-1}$. Then the impulse on the ball is

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Remember to consider direction when calculating change in velocity for impulse: $Impulse = m(v - u)$
Updated On: May 12, 2025
  • 0.5 kg ms$^{-1}$
  • 1.0 kg ms$^{-1}$
  • 1.50 kg ms$^{-1}$
  • 1.5 kg ms$^{-1}$
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The Correct Option is D

Solution and Explanation

Mass $m = 50 \text{ g} = 0.05 \text{ kg}$
Initial velocity $u = 10$ ms$^{-1}$, final velocity $v = -20$ ms$^{-1}$ (since it reverses direction)
Impulse $= m(v - u) = 0.05(-20 - 10) = 0.05(-30) = -1.5$ kg ms$^{-1}$
Magnitude of impulse $= 1.5$ kg ms$^{-1}$
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