Question:
A ball of mass 0.5 kg moving horizontally at \( 10\, \text{ms}^{-1} \) strikes a vertical wall and rebounds with speed \( V \). The change in linear momentum is 8.0 kg·m/s. Find the magnitude of \( V \).
A ball of mass 0.5 kg moving horizontally at \( 10\, \text{ms}^{-1} \) strikes a vertical wall and rebounds with speed \( V \). The change in linear momentum is 8.0 kg·m/s. Find the magnitude of \( V \).
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Change in momentum = Final momentum (opposite) + Initial momentum (when direction reverses).
Updated On: May 18, 2025
- 6.0 m/s
- 9.0 m/s
- 26.0 m/s
- 13.0 m/s
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The Correct Option is A
Solution and Explanation
Initial momentum = \( 0.5 \cdot 10 = 5 \, \text{kg·m/s} \) (right)
Final momentum = \( 0.5 \cdot V \) (left)
Change in momentum = \( 0.5 \cdot V + 5 = 8 \)
\[ \Rightarrow 0.5V = 3 \Rightarrow V = 6 \, \text{m/s} \]
Final momentum = \( 0.5 \cdot V \) (left)
Change in momentum = \( 0.5 \cdot V + 5 = 8 \)
\[ \Rightarrow 0.5V = 3 \Rightarrow V = 6 \, \text{m/s} \]
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