A ball is thrown vertically upward. It has a speed of \(10\ m/s\) when it has reached one half of its maximum height. How high does the ball rise?
(Take \(g = 10\, m/s^2\))
(Take \(g = 10\, m/s^2\))
- 10 m
- 5 m
- 15 m
- 20 m
The Correct Option is A
Solution and Explanation
\(v^2 =u^2 - 2gh\)
After reaching maximum height velocity becomes zero.
\(0 = (10)^2 - 2 \times 10 \times \frac{h}{2}\)
\(\therefore h = \frac{200}{20}\)
\(h= 10\, m.\)
So, the correct option is (A): 10 m
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Concepts Used:
Motion in a straight line
The motion in a straight line is an object changes its position with respect to its surroundings with time, then it is called in motion. It is a change in the position of an object over time. It is nothing but linear motion.
Types of Linear Motion:
Linear motion is also known as the Rectilinear Motion which are of two types:
- Uniform linear motion with constant velocity or zero acceleration: If a body travels in a straight line by covering an equal amount of distance in an equal interval of time then it is said to have uniform motion.
- Non-Uniform linear motion with variable velocity or non-zero acceleration: Not like the uniform acceleration, the body is said to have a non-uniform motion when the velocity of a body changes by unequal amounts in equal intervals of time. The rate of change of its velocity changes at different points of time during its movement.