Question:

A artificial satellite is going round the earth assumed to be uniform sphere. Its period t will depend on the density $ \rho $ by the relation (k is numerical constant)

Updated On: Jun 11, 2023
  • $ t=k{{\rho }^{1/2}} $
  • $ t=k\rho $
  • $ t=k{{\rho }^{-1}} $
  • $ t=k{{\rho }^{-1/2}} $
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The Correct Option is D

Solution and Explanation

Time period of satellite is given by $ t=2\pi \sqrt{\frac{{{R}^{3}}}{GM}}=2\pi \sqrt{\frac{{{R}^{3}}}{G\left( \frac{4}{3} \right)\pi {{R}^{3}}\rho }} $ $ \Rightarrow $ $ t\propto \frac{1}{\sqrt{\rho }} $
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Concepts Used:

Gravitation

In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.

Newton’s Law of Gravitation

According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,

  • F ∝ (M1M2) . . . . (1)
  • (F ∝ 1/r2) . . . . (2)

On combining equations (1) and (2) we get,

F ∝ M1M2/r2

F = G × [M1M2]/r2 . . . . (7)

Or, f(r) = GM1M2/r2

The dimension formula of G is [M-1L3T-2].