Let the work be represented by \( W \), and let the rates of work for A, B, and C be \( A \), \( B \), and \( C \) respectively.
From the given information:
\[
\frac{W}{72} = A + B, \quad \frac{W}{120} = B + C, \quad \frac{W}{90} = A + C
\]
We want to find the time taken by A alone. First, add all three equations:
\[
\frac{W}{72} + \frac{W}{120} + \frac{W}{90} = (A + B) + (B + C) + (A + C)
\]
Simplifying:
\[
\frac{W}{72} + \frac{W}{120} + \frac{W}{90} = 2A + 2B + 2C
\]
Now simplify further to find \( A \) and calculate the time. This simplifies to \( A = 60 \) days. Thus, A alone can do the work in 60 days.