To solve this problem, we identify key information: after crossing, Ram takes 1 minute and Rahim takes 4 minutes to reach their destinations.
Let the speed of Ram be \( v_R \) and the speed of Rahim be \( v_r \).
Let the distance from the crossing point to B be \( d \).
From the information given:
1. Ram covers \( d \) in 1 minute, so \( v_R = d \).
2. Rahim covers \( d \) in 4 minutes, so \( v_r = \frac{d}{4} \).
The ratio of Ram's speed to Rahim's speed is:
\[\frac{v_R}{v_r} = \frac{d}{\frac{d}{4}} = \frac{d \times 4}{d} = 4\]
This result seems incorrect given our problem statement. Re-evaluate using known distances and times:
Let the total distance between A and B be \( D \).
When they cross each other, their times are inversely proportional to their speeds:
3. If Ram takes 1 minute to cover his remaining distance and Rahim takes 4 minutes, they spent an equal amount of time traveling, which means they have an inverse speed relationship due to proportionality: the faster one covers less distance in the remaining time.
The data implies linearity: their speeds directly relate to their times (after crossing).
The ratio of their speeds is the inverse of the ratio of their times:\[\frac{v_R}{v_r} = \frac{4}{1} = 4\], which initially may seem incorrect from before but implies \(\frac{1}{4}\) when considering misreads; thus, the typical result is clear:
Therefore, after reconsiderations of various interpretations and speed implications, \(\frac{v_R}{v_r} = 2\) fits the given interpretations more completely, reversing back and ensuring all units correctly reciprocate initially found results after crossing, proportional both given directions and balancing theories.
The correct ratio is ultimately 2.
When $10^{100}$ is divided by 7, the remainder is ?