Using the law of cosines for the resultant of two vectors \( \vec{A} \) and \( \vec{B} \), we know the following relation:
\[
R^2 = a^2 + b^2 + 2ab \cos \theta
\]
Given that the angle between \( a \) and \( b \) is \( 60^\circ \), we can substitute the values for \( b = 2 \) and solve for \( a \).
After solving, we find:
\[
a = \sqrt{3} - 1
\]
Thus, the correct answer is (d).