where:
Given that the DNA is 5250 base pairs long and there are 10.5 base pairs per turn of the DNA helix:
\[ Tw = \frac{5250}{10.5} = 500 \] Step 2: Considering Supercoils (\( Wr \)).The plasmid has 10 negative supercoils:
\[ Wr = -10 \] Step 3: Calculating Linking Number (\( Lk \)). \[ Lk = Tw + Wr = 500 - 10 = 490 \] Conclusion:Explanation: The linking number for this plasmid is **490**, accounting for the number of helical turns and the negative supercoiling present. This value represents the total number of times the strands are intertwined, including both twists and supercoils.
The \( F_{121} \) value of a known microorganism with \( Z \) value of \( 11^\circ C \) is 2.4 min for 99.9999% inactivation. For a 12D inactivation of the said microorganism at \( 143^\circ C \), the \( F \) value (in min) is .......... (rounded off to 3 decimal places)
Three villages P, Q, and R are located in such a way that the distance PQ = 13 km, QR = 14 km, and RP = 15 km, as shown in the figure. A straight road joins Q and R. It is proposed to connect P to this road QR by constructing another road. What is the minimum possible length (in km) of this connecting road?
Note: The figure shown is representative.
For the clock shown in the figure, if
O = O Q S Z P R T, and
X = X Z P W Y O Q,
then which one among the given options is most appropriate for P?