Question:

A $220\, volt$ input is supplied to a transformer. The output circuit draws a current of $2.0$ ampere at $440\, volts$. If the efficiency of the transformer is $80\%$, the current drawn by the primary windings of the transformer is

Updated On: Jul 13, 2024
  • 3.6 ampere
  • 2.8 ampere
  • 2.5 ampere
  • 5.0 ampere
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The Correct Option is D

Solution and Explanation

Here,
Input voltage, $V_p$ = 220 V
Output voltage, $V_s$ = 440 V
Input current, $I_p= ?$
Output current, $I_s$ = 2 A
Efficiency of the transformer,$\eta$=80%
Efficiency of the transformer, $\eta=\frac{\text{Output power}}{\text{Input power}}$
$ \eta=\frac{V_sI_s}{V_pI_p}$
or $ I_p=\frac{V_sI_s}{\eta V_p}=\frac{(440 \, V)(2 \, A)}{\big(\frac{80}{100}\big)(220 \, V)}$
$=\frac{(440 \, V)(2 \, A)(100)}{(80)(220 \, V)}$
$=5 A$
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