Question:

A 2 kg object is hanging vertically from a rope. The tension in the rope is 15 N. What is the acceleration of the object? (Assume \( g = 9.8 \, \text{m/s}^2 \))

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If the tension in a rope is less than the weight of an object, the object will experience a downward acceleration.
Updated On: Apr 15, 2025
  • \( 1.0 \, \text{m/s}^2 \)
  • \( 2.0 \, \text{m/s}^2 \)
  • \( 0.5 \, \text{m/s}^2 \)
  • \( 3.0 \, \text{m/s}^2 \)
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The Correct Option is A

Solution and Explanation

The net force on the object is the difference between the tension and the weight of the object: \[ F_{\text{net}} = T - mg \] Where: - \( T = 15 \, \text{N} \) is the tension in the rope, - \( m = 2 \, \text{kg} \) is the mass of the object, - \( g = 9.8 \, \text{m/s}^2 \) is the acceleration due to gravity. The weight of the object is: \[ mg = 2 \times 9.8 = 19.6 \, \text{N} \] Now calculate the net force: \[ F_{\text{net}} = 15 \, \text{N} - 19.6 \, \text{N} = -4.6 \, \text{N} \] The negative sign indicates that the object is accelerating downward. Using Newton's second law: \[ a = \frac{F_{\text{net}}}{m} = \frac{-4.6}{2} = -2.3 \, \text{m/s}^2 \] Thus, the acceleration of the object is \( 2.3 \, \text{m/s}^2 \) downward.
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