To determine the pressure inside the flask, we will use the ideal gas law equation: \( PV = nRT \).
Here, \( P \) is the pressure, \( V \) is the volume, \( n \) is the number of moles, \( R \) is the ideal gas constant, and \( T \) is the temperature in Kelvin.
First, convert the mass of oxygen to moles. The molar mass of \( O_2 \) is approximately 32 g/mol.
\( n = \frac{64 \text{ g}}{32 \text{ g/mol}} = 2 \text{ mol} \)
Next, convert the temperature from Celsius to Kelvin: \( T = 27 + 273 = 300 \text{ K} \).
Now, substitute the known values into the ideal gas law: \[ P \cdot 10 \text{ L} = 2 \text{ mol} \times 0.0831 \text{ L bar K}^{-1} \text{ mol}^{-1} \times 300 \text{ K} \] \[ P \cdot 10 = 49.86 \text{ L bar} \] \[ P = \frac{49.86}{10} \] \[ P = 4.986 \text{ bar} \]
Rounding to one decimal place, the pressure is approximately 4.9 bar.

Consider a water tank shown in the figure. It has one wall at \(x = L\) and can be taken to be very wide in the z direction. When filled with a liquid of surface tension \(S\) and density \( \rho \), the liquid surface makes angle \( \theta_0 \) (\( \theta_0 < < 1 \)) with the x-axis at \(x = L\). If \(y(x)\) is the height of the surface then the equation for \(y(x)\) is: (take \(g\) as the acceleration due to gravity) 
The matter is made up of very tiny particles and these particles are so small that we cannot see them with naked eyes.
The three states of matter are as follows: