To determine the pressure inside the flask, we will use the ideal gas law equation: \( PV = nRT \).
Here, \( P \) is the pressure, \( V \) is the volume, \( n \) is the number of moles, \( R \) is the ideal gas constant, and \( T \) is the temperature in Kelvin.
First, convert the mass of oxygen to moles. The molar mass of \( O_2 \) is approximately 32 g/mol.
\( n = \frac{64 \text{ g}}{32 \text{ g/mol}} = 2 \text{ mol} \)
Next, convert the temperature from Celsius to Kelvin: \( T = 27 + 273 = 300 \text{ K} \).
Now, substitute the known values into the ideal gas law: \[ P \cdot 10 \text{ L} = 2 \text{ mol} \times 0.0831 \text{ L bar K}^{-1} \text{ mol}^{-1} \times 300 \text{ K} \] \[ P \cdot 10 = 49.86 \text{ L bar} \] \[ P = \frac{49.86}{10} \] \[ P = 4.986 \text{ bar} \]
Rounding to one decimal place, the pressure is approximately 4.9 bar.
A bob of heavy mass \(m\) is suspended by a light string of length \(l\). The bob is given a horizontal velocity \(v_0\) as shown in figure. If the string gets slack at some point P making an angle \( \theta \) from the horizontal, the ratio of the speed \(v\) of the bob at point P to its initial speed \(v_0\) is :
The matter is made up of very tiny particles and these particles are so small that we cannot see them with naked eyes.
The three states of matter are as follows: