Question:

${ }_{92}^{238} U$ is known to undergo radioactive decay to form ${ }_{82}^{206} Pb$ by emitting alpha and beta particles. A rock initially contained $68 \times 10^{-6} g$ of ${ }_{92}{ }^{238} U$. If the number of alpha particles that itwould emit during its radioactive decay of ${ }_{92}^{238} U$ to ${ }_{82}{ }^{206} Pb$ in three half-lives is $Z \times 10^{18}$, then what is the value of $Z$ ?

Updated On: May 13, 2024
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Correct Answer: 1.21

Solution and Explanation

The value of Z is 1.21

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Concepts Used:

Nuclei

In the year 1911, Rutherford discovered the atomic nucleus along with his associates. It is already known that every atom is manufactured of positive charge and mass in the form of a nucleus that is concentrated at the center of the atom. More than 99.9% of the mass of an atom is located in the nucleus. Additionally, the size of the atom is of the order of 10-10 m and that of the nucleus is of the order of 10-15 m.

Read More: Nuclei

Following are the terms related to nucleus:

  1. Atomic Number
  2. Mass Number
  3. Nuclear Size
  4. Nuclear Density
  5. Atomic Mass Unit