To determine the length of the wire in metres when 66 cubic centimetres of silver is drawn into a wire of 1mm diameter, we start by recognizing the shape and properties of the wire. The wire has a cylindrical shape, and we're given two key parameters: the volume (\(V\)) of the silver and the diameter (\(d\)) of the wire.
The volume \(V\) of a cylinder is calculated using the formula:
\(V = \pi r^2 h\)
where:
The diameter of the wire is 1mm, which is \(0.1 \, \text{cm}\) (since \(1 \, \text{mm} = 0.1 \, \text{cm}\)). Thus, the radius \(r\) is half of this diameter:
\(r = \frac{0.1}{2} = 0.05 \, \text{cm}\)
Substituting the known values into the volume formula, we have:
\(66 = \pi (0.05)^2 h\)
Solving for \(h\), the length of the wire, we get:
\(66 = \pi \times 0.0025 \times h\)
\(66 = 0.00785h\)
\(h = \frac{66}{0.00785}\)
Calculating the above, we find:
\(h \approx 8403.82 \, \text{cm}\)
Since we need the length in metres, we convert centimetres to metres by dividing by 100:
\(h \approx \frac{8403.82}{100} = 84.0382 \, \text{m}\)
Rounding this, the length of the wire is approximately 84 metres, which matches the correct answer option.
Answer: 84 metres
In the given figure, the numbers associated with the rectangle, triangle, and ellipse are 1, 2, and 3, respectively. Which one among the given options is the most appropriate combination of \( P \), \( Q \), and \( R \)?
Find the number of triangles in the given figure.
A regular dodecagon (12-sided regular polygon) is inscribed in a circle of radius \( r \) cm as shown in the figure. The side of the dodecagon is \( d \) cm. All the triangles (numbered 1 to 12 in the figure) are used to form squares of side \( r \) cm, and each numbered triangle is used only once to form a square. The number of squares that can be formed and the number of triangles required to form each square, respectively, are:
Find the missing code:
L1#1O2~2, J2#2Q3~3, _______, F4#4U5~5, D5#5W6~6